(x^2-6x+9)/(4x^2-36)*(4x+12)/(5x-15)

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Solution for (x^2-6x+9)/(4x^2-36)*(4x+12)/(5x-15) equation:


D( x )

5*x-15 = 0

4*x^2-36 = 0

5*x-15 = 0

5*x-15 = 0

5*x-15 = 0 // + 15

5*x = 15 // : 5

x = 15/5

x = 3

4*x^2-36 = 0

4*x^2-36 = 0

4*x^2 = 36 // : 4

x^2 = 9

x^2 = 9 // ^ 1/2

abs(x) = 3

x = 3 or x = -3

x in (-oo:-3) U (-3:3) U (3:+oo)

(((x^2-(6*x)+9)/(4*x^2-36))*(4*x+12))/(5*x-15) = 0

(((x^2-6*x+9)/(4*x^2-36))*(4*x+12))/(5*x-15) = 0

((x^2-6*x+9)*(4*x+12))/((4*x^2-36)*(5*x-15)) = 0

x^2-6*x+9 = 0

x^2-6*x+9 = 0

DELTA = (-6)^2-(1*4*9)

DELTA = 0

x = 6/(1*2)

x = 3 or x = 3

(x-3)^2 = 0

((x-3)^2*(4*x+12))/((4*x^2-36)*(5*x-15)) = 0

( 4*x+12 )

4*x+12 = 0 // - 12

4*x = -12 // : 4

x = -12/4

x = -3

( x-3 )

x-3 = 0 // + 3

x = 3

x in { -3}

x in { 3}

x belongs to the empty set

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